Question

Probably my coding isn’t so good and some lines wouldn’t make much sense or are not necessary, but the code purpose is dead-simple:

I want to create a function that uses an input(string), and convert it as an integer, which is going to be use in a math problem.
Plus: I want my code to interpret a random generated number and print it as its string equivalent:

### 'one' --> 1
### 'zero' --> 0 

import random

##'one' == 1
##'zero' == 0

def name_to_number(name):
    if name == 'one':
        return 1

def number_to_name(comp_number):
    if comp_number == 1:
        return 'one'

def lit_for_num(name):
    '''(str) -> str'''

    comp_number = random.randrange(0,1)
    equation = (abs(comp_number - int(name)))
    if equation == 0:
        print('Hallo!')
        return 'Computer draws' + comp_number
    else:
        return 'Computer draws 0'

Any help is very much thanked.

Answer 1

The first problem is that you seem to be using one as input, and hence
int('one') will give you that error.

Secondly, in:

comp_number = random.randrange(0,1)
...
if equation == 0:
    print('Hallo!')
    return 'Computer draws' + comp_number
else:
    return 'Computer draws 0'

the else clause will always be called because comp_number is always 0.

rand.randrange is similar to choice(range(start, stop, step)), which means randrange(0,1) will always return 0. You would want randrange(0,2) instead if you want to either 0 or 1. Or, use random.randint(0,1) instead, which will include end points 0 and 1.

As a bonus, to process text number to number, you may want to consider text2num written by Greg Hewgill.