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Asked: 2026-05-27T09:02:15+00:00

proc_obj = -> proto { print proto; puts(World)} puts proc_obj[Hi] puts proc_obj.call(Hello) #Is this

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proc_obj = -> proto { print proto; puts("World")}

puts proc_obj["Hi"]

puts proc_obj.call("Hello") #Is this is the same as above

please refer me to some link to demystify this …

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1 Answer

  1. Editorial Team

    What is happening to that lambda is that you’re calling its [] method, which causes the lambda to be executed with the argument "Hi". And yes, calling call is the same as calling [].

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