Question

Program for work with arrays in dynamic memory.
Need equivalent for C. Can anybody help?

const int n = 6;
char **words = (char**) malloc(n *sizeof(char*));
for(int i = 0 ; i < n; i++)
    words[i] = (char*)malloc( 50 * sizeof(int));

for(int i = 0; i < n; i++) 
{
    cin>>words[i];
}

cout<<endl;
for(int i = 0; i < n; i++) 
{
    if(words[i][0] == 'q')
        cout<<words[i]<<endl;
}

Answer 1

The only C++ parts there are cin and cout; you can change them easily:

cin>>words[i];

becomes

scanf("%s", words[i]);

or

gets(words[i]);

while

cout<<words[i]<<endl;

becomes

puts(words[i]);

By the way, in the cin/scanf/gets you have a potential buffer overflow, since you are allocating space for 6 characters but you are accepting input of any length. You should do instead:

scanf("%6s", words[i]);

or (more maintainable, since it uses n directly)

fgets(words[i], n, stdin);

(although this will include the trailing \n in the string)