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Home/ Questions/Q 784387
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T20:42:19+00:00 2026-05-14T20:42:19+00:00

Program: program s; type info = record name, surname: string; min, sek: integer; end;

  • 0

Program:

program s;
type 
  info = record
    name, surname: string;
    min, sek: integer;
  end;

  type arrays = array[1..50] of info;

var 
  c, b: text;
  A: arrays;
  gr_sk, grup_dal: integer;

begin
  assign(c, 'info.txt'); 
  reset(c);
  read(c, gr_sk);
  read(c, grup_dal);
  id := 1;

  read(c, A[id].name);
  read(c, A[id].sek);

  close(c);

end.

info.txt file:

3
4
yhgf
4

Please, tell me what is wrong with that. It says that it is bad number format for line 19 I guess.

If I change min, sek: integer; to min, sek: string; then it works. So as I understand, it reads number like string. How can it be? I have never experienced that before.

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  1. Editorial Team
    Editorial Team
    2026-05-14T20:42:19+00:00Added an answer on May 14, 2026 at 8:42 pm

    This is what i think

    You are trying to read ‘yhgf’ into an integer (gr_sk), so when read reads, it throws an error because ‘yhgf’ can’t be transformed into an integer.

    What should you do?

    Well, I think that you can read it into a string, validate that it is a number, and then transform it into an integer. Frankly, I don’t remember the Pascal way to do it. After googling around, found val procedure.

    Val converts the integer or real
    number that is represented by the
    characters in the string Source and
    places it into x.

    Some tips on string functions / procedures:

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