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Home/ Questions/Q 6795377
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T18:20:15+00:00 2026-05-26T18:20:15+00:00

public class A{ } A a = new A(){{ final int x = 1;

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public class A{
}

A a = new A(){{
    final int x = 1; // IT HAS TO BE FINAL HERE. WHY?
}};

A aa = new A(){
    int x = 1; // THIS NEED NOT BE FINAL. WHY?
    final int y = 1; // STILL FINAL IS ALLOWED HERE. WHY?
    public int getX(){
        return x;
    }
};

Can somebody please answer the questions mentioned inside the snippet?

Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-26T18:20:16+00:00Added an answer on May 26, 2026 at 6:20 pm
    A a = new A(){{
        final int x = 1; // IT HAS TO BE FINAL HERE. WHY?
    

    It needn’t.

    The difference between the two is that in the first case, you’re writing the code used to initialize each object in the double braces. That x is its local variable (doesn’t have anything to do with objects of class A).

    In the second case, you’re defining the classes body. x would be its member variable. If it were static, its class variable. If final a (basically) constant.

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