Question

public class A{
    List m;
    public A(int a, int b) {m=new List(); ...}
}


public class B : A{
    List a;
    List b;
    public B(){...}  //constructor1
    public B(int a, int b) : base(a,b){...} //constructor2
}

My question is I need to initialize both list a and b in class B. If I put them in the constructor1, how can I call constructor1 in constructor2? I don’t want to rewrite the initialization statements in constructor2 again. Thanks!

Answer 1

It sounds to me that you simply have the dependency backwards mentally. I think what you want to do is this:

public class B : A {
    List _a;
    List _b;

    public B(int a, int b) : base(a, b) {
        // this calls the base constructor

        // presumably you're initializing _a and _b in here?
        _a = new List();
        _b = new List();
    }

    // let x and y be your defaults for a and b
    public B() : this(x, y) {
        // this calls the this(a, b) constructor,
        // which in turn calls the base constructor
    }
}