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Home/ Questions/Q 6067945
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T09:39:47+00:00 2026-05-23T09:39:47+00:00

public class BaseClass { public void start() { // do something } } public

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public class BaseClass {
   public void start() {
      // do something
   }
}

public class ClassA extends BaseClass {

}

ClassA c = new ClassA();
c.start();

In the following code I want to use the start() method as it was defined in the super class, I have seen in a lot of other developer’s codes that they override the method in the super class and then they call the super. is there a reason for that?

public class ClassA extends BaseClass {
   @Override
   public void start() {
      super.start();
   }
}
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  1. Editorial Team
    Editorial Team
    2026-05-23T09:39:47+00:00Added an answer on May 23, 2026 at 9:39 am

    Clarity? Some developers feel it is clearer to show the method in the subclass. I disagree. It’s redundant info.

    At least since Java 5, you could add an @Override so the compiler will tell you if the signature changes/disappears.

    Except for constructors. For constructors, you really do have to create your own with the same signature and delegate upwards. In this case, omitting isn’t equivalent though.

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