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Home/ Questions/Q 354563
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T11:56:09+00:00 2026-05-12T11:56:09+00:00

public class Ex7 { private int fld; private void meth(int val) { fld =

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public class Ex7 {
    private int fld;

    private void meth(int val) {
        fld = val;
        System.out.println(" meth() -> fld = " + fld);
    }

    public class Ex7Inner1 {
        void operateOnFld() {
            fld = 12;
        }

        void operateOnMeth() {
            meth(10);
        }

        public void bar() {
            System.out.println(" bar() ");
        }
    }

    class Ex7Inner2 {
        Ex7Inner1 i1 = new Ex7Inner1();
        // how to call i1.bar() ??
        i1.bar();
    }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T11:56:10+00:00Added an answer on May 12, 2026 at 11:56 am

    Your problem is that you need to call i1.bar() inside a function. For example

    class Ex7Inner2 {
        Ex7Inner1 i1 = new Ex7Inner1();  // this is now a field of the Ex7Inner2 class
        public void callBar() {
            i1.bar();                    // this will work
        }
    }
    

    In the future, you may find that people are able to be more helpful if you include the error you get in your question, which I’ll do now. When you try to compile the code your way, you get an error that looks like

    Ex7.java:26: <identifier> expected
      i1.bar();
            ^
    1 error
    

    This is because the only thing you can do outside of a method (like you originally had it) is declare variables. So it was expecting an “identifier” by which it meant “the name of the variable you are declaring”. So if you had said

    String s;
    

    then s would have been the identifier.

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