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Home/ Questions/Q 8475053
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T17:47:29+00:00 2026-06-10T17:47:29+00:00

public class Main { public static void main(String[] args){ System.out.println(X.Y.Z); } } class X

  • 0
public class Main {
    public static void main(String[] args){
        System.out.println(X.Y.Z);
    }
}

class X {
    static class Y {
        static String Z = "Result 1";
    }
    static C Y = new C();
}

class C {
    String Z = "Result 2";
}  

Sometime output is "Result 1" and sometime output is "Result 2". Can you explain why?

I am using JDK 1.6_33.

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  1. Editorial Team
    Editorial Team
    2026-06-10T17:47:30+00:00Added an answer on June 10, 2026 at 5:47 pm

    This is Java Puzzler #68 – it should always print Result 2. Quote:

    It turns out that there is a rule that governs program behavior under these circumstances. When a
    variable and a type have the same name and both are in scope, the variable name takes
    precedence [JLS 6.5.2]. The variable name is said to obscure the type name [JLS 6.3.2]. Similarly,
    variable and type names can obscure package names. This rule is indeed obscure, and any
    program that depends on it is likely to confuse its readers.

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