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Home/ Questions/Q 8780361
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T20:01:23+00:00 2026-06-13T20:01:23+00:00

public class MyClass { private String string; private Object[] objects; // constructor 1 public

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public class MyClass {

    private String string;
    private Object[] objects;

    // constructor 1
    public MyClass(String string, Object... objects) {
        this.string = string;
        this.objects = objects;
    }

    // constructor 2
    public MyClass(String string) {
        this.string = string;
    }

    public static void main(String[] args) {
        MyClass myClass = new MyClass("foobar");
    }

}

In that case, how did the Java compiler decide to use constructor 2 instead of constructor 1? Why no The constructor ... is ambiguous or a similar error occurs?

PS: the question works with classic methods too.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T20:01:24+00:00Added an answer on June 13, 2026 at 8:01 pm

    It’s always the most specific method that is called.

    new MyClass("foobar");
    

    searches to call that constructor which takes an object of type String as it’s only argument.

    and, var-args method will be used iff matching non-var-args method doesn’t exist.

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