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Home/ Questions/Q 7684127
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T18:57:14+00:00 2026-05-31T18:57:14+00:00

public class Node { private Node nextNode; @Override public int hashCode() { //How to

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public class Node {
    private Node nextNode;

    @Override
    public int hashCode() {
        //How to implement this?
        //Because you just have a attribute which is a reference.
        //I think the attribute is almost useless, because if you use the HashCode of the attribute, you will finally fall into a useless loop.
        //Thus, I think you should find a way to represent the HashCode of reference (instance) itself.
    }
}

From the comment in the code, my question is actually how to uniquely identify reference itself, like address in C.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T18:57:15+00:00Added an answer on May 31, 2026 at 6:57 pm

    If you want the Node‘s hash-code to represent its own reference — that is, if you’re not overriding equals(Object) — then you don’t need to override hashCode() at all.

    If you want the Node‘s hash-code to represent the reference of its nextNode — that is, if your equals(Object) looks something like this:

    @Override
    public boolean equals(Object that)
    {
        return ((that instanceof Node) && (nextNode == ((Node) that).nextNode));
    }
    

    — then you can use the JDK’s System.identityHashCode(Object) utility method:

    @Override
    public int hashCode()
    {
        return System.identityHashCode(nextNode);
    }
    
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