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Home/ Questions/Q 6919991
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T10:05:30+00:00 2026-05-27T10:05:30+00:00

public class Test { public static void main(String[] args) { int[] arr = new

  • 0
public class Test {
    public static void main(String[] args) {
        int[] arr = new int[5];
        arr[0]    = 1;
        method(arr);
        System.out.println(arr[0]);
    }

    private static void method(int[] array)
    {
        array[0] = 2;
    }
}

After invoking method, arr[0] becomes 2. Why is that!?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T10:05:30+00:00Added an answer on May 27, 2026 at 10:05 am

    You can call set methods on objects passed to a method. Java is pass by value, which means that you can’t replace an object in a method, though you can call set methods on an object.

    If Java were pass by reference, this would pass:

    public class Test {
    
    public static void main(String[] args) {
        Test test = new Test();
        int j = 0;
        test.setToOne(j);
        assert j == 1;
    }
    
    public void setToOne(int i) {
        i = 1;
    }
    }
    
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