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Home/ Questions/Q 9201463
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T23:00:52+00:00 2026-06-17T23:00:52+00:00

public class Test { public static void main(String[] args) { String s = null;

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public class Test {
    public static void main(String[] args) {

        String s = null;
        String s1 = null;
        Integer i = null;
        Integer i1 = null;

        System.out.println(s+i);
        System.out.println(i+s);
        System.out.println(s+s1);

        try {
            System.out.println(i+i1);
        } catch (NullPointerException np) {         
            System.out.print("NullPointerException");       
        }
    }

}

The question is simple – why do I receive a NullPointerException only at the last line?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T23:00:54+00:00Added an answer on June 17, 2026 at 11:00 pm

    Your code makes use of two different additive operators. The first three lines use string concatenation, whereas the last one uses numeric addition.

    String concatenation is well-defined to turn null into "null":

    • If the reference is null, it is converted to the string "null" (four ASCII characters n, u, l, l).

    Hence there is no NPE.

    Adding two Integer objects together requires them to be unboxed. This results in the null reference being dereferenced, which leads to the NPE:

    • If r is null, unboxing conversion throws a NullPointerException
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