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Home/ Questions/Q 8709983
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T04:30:24+00:00 2026-06-13T04:30:24+00:00

public class test { public static void main(String[] args) throws Exception { final int

  • 0
public class test {

    public static void main(String[] args) throws Exception {

        final int num = 111;

        new Thread() {
            @Override
            public void run() {
                num = 222;
            }
        }.start();

    }
}

I want to change the value of num however I can only do that if I set it to final which would not let me modify this. In other languages such as C we can use pointers but Java cannot?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T04:30:26+00:00Added an answer on June 13, 2026 at 4:30 am

    Java has neither closure nor pointers.

    A solution would be to make the num static in the class :

    public class test {
        static int num = 111;
        public static void main(String[] args) throws Exception {
            new Thread() {
                @Override
                public void run() {
                    num = 222;
                }
            }.start();
        }
    }
    

    Another solution would be to use an object like AtomicInteger. You can’t change the value of the variable but you can change the content of the value :

    public class test {
        public static void main(String[] args) throws Exception {
            final AtomicInteger num = new AtomicInteger(111);
            new Thread() {
                @Override
                public void run() {
                    num.set(222);
                }
            }.start();
        }
    }
    
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