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Home/ Questions/Q 6009405
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T01:57:56+00:00 2026-05-23T01:57:56+00:00

public class ThreadSafe implements ITaskCompletionListener { private final Set<String> taskIds = new HashSet<String>(); private

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public class ThreadSafe implements ITaskCompletionListener {

private final Set<String> taskIds = new HashSet<String>();
private final Set<String> successfulIds = new HashSet<String>();
private final Set<String> cancelledIds = new HashSet<String>();
private final Set<String> errorIds = new HashSet<String>();

public ThreadSafe() {

}

// invoked concurrently
@Override
public void onCancel(String pTaskId) {
    remove(pTaskId);
    cancelledIds.add(pTaskId);
}

// invoked concurrently
@Override
public void onError(String pTaskId) {
    remove(pTaskId);
    errorIds.add(pTaskId);
}

// invoked concurrently
@Override
public void onSuccess(String pTaskId) {
    remove(pTaskId);
    successfulIds.add(pTaskId);
}

private void remove(String pTaskId) {
    taskIds.remove(pTaskId);
}

}
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  1. Editorial Team
    Editorial Team
    2026-05-23T01:57:57+00:00Added an answer on May 23, 2026 at 1:57 am

    This code is riddled with thread-safety problems.

    HashSet is not thread-safe (it is based on the non-threads-safe HashMap – race conditions in which can end up causing infinite loops).

    Secondly, there is no atomicity between an ID being in the taskIds set and it being added to one of the others, so a task’s existence is ephemeral.

    Thirdly, the code implicitly assumes that the task state is simply inProgress -> success|error|cancel and that there is no concurrent task execution. If this is not true then the code fails.

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