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Home/ Questions/Q 109695
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Asked: May 11, 20262026-05-11T02:06:36+00:00 2026-05-11T02:06:36+00:00

public class WrapperTest { static { print(10); } static void print(int x) { System.out.println(x);

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public class WrapperTest {     static {         print(10);     }      static void print(int x) {         System.out.println(x);         System.exit(0);     } } 

In the above code System.exit(0) is used to stop the program. What argument does that method take? Why do we gave it as 0. Can anyone explain the concept?

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  1. 2026-05-11T02:06:36+00:00Added an answer on May 11, 2026 at 2:06 am

    From the JAVA Documentation:

    The argument serves as a status code; by convention, a nonzero status code indicates abnormal termination.

    And Wikipedia adds additional information.

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