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Home/ Questions/Q 8962859
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T16:13:43+00:00 2026-06-15T16:13:43+00:00

public delegate T GenDel<T>(); class Program { public static void genMet<T>(GenDel<T> d) { }

  • 0
public delegate T GenDel<T>();

class Program
{
    public static void genMet<T>(GenDel<T> d) { }

    static void Main(string[] args)
    {           
        genMet(new GenDel<string>(() => "Works"));
        genMet(() => "Works");
    }
}

In above example the generic method receives lambda expression as a parameter ( genMet(() => "Works"); ), and from this lambda expression method is able to infer parameter types.

Why isn’t method also able to infer parameter type in the next example, where instead of lambda expression we pass a delegate instance as a parameter:

        genMet(new GenDel(() => "Doesn't work")); // Error: Using the generic type 'GenDel<T>' 
                                                  // requires 1 type arguments
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T16:13:44+00:00Added an answer on June 15, 2026 at 4:13 pm

    Type inference only applies to generic methods, not generic types or their constructors.

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