public double delhi(Integer a)
{
return (int)a;
}
In case you do not get it, look at the return type of the method
public double delhi(Integer a) { return (int)a; } In case you do not get
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public double delhi(Integer a)
{
return (int)a;
}
In case you do not get it, look at the return type of the method
The return type declared on a method is used to allocate a memory on the stack to store the return value. Here, by declaring return type as
doublecompiler will allocate more space (64-bit) than required by the actual return value, anint(32-bit). Therefore, there is no loss of data expected on this(up)conversion. Therfore, both compiler and runtime, does not complain and it works. Try the opposite, set return type asintand return alongordouble. You will get compiler error because there will be potential of data corruption.