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Home/ Questions/Q 7509699
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T22:59:43+00:00 2026-05-29T22:59:43+00:00

public interface IMy<T> { T Implementer { get; } } public class MyClass :

  • 0
public interface IMy<T>
{
    T Implementer
    {
        get;
    }
}
public class MyClass : IMy<MyClass>
{
    ...
}

But what I want is this:

public interface IMy
{
    I Implementer
    {
        get;
    }
}

Please accept that for some ca-razy reason I need an interface that defines a method that returns in the type of the implementer. No? Okay, suppose it’s something like an XML explorer, so call my interface ITree for example.

Interfaces primarily help me organize (separate), but when I have one that requires I rely on a convention, it seems to defeat the purpose.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T22:59:45+00:00Added an answer on May 29, 2026 at 10:59 pm

    You want to be able to say “The interface should know who implements it, and automatically provide the implementer’s type in its definition, to be inherited by the implementer”? Like

    public interface IMy
    {
        ImplicitImplementerType SomeProperty
        {
            get;
        }
    }
    

    I’m pretty sure that is impossible. Such a thing may be achieved in more dynamic languages though (I’m guessing here).

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