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Home/ Questions/Q 5964507
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T19:26:43+00:00 2026-05-22T19:26:43+00:00

public static String removeChar(String s, char c) { StringBuffer r = new StringBuffer( s.length()

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public static String removeChar(String s, char c) {
  StringBuffer r = new StringBuffer( s.length() );
  r.setLength( s.length() );
  int current = 0;
  for (int i = 0; i < s.length(); i ++) {
     char cur = s.charAt(i);
     if (cur != c) r.setCharAt( current++, cur );
  }
  return r.toString();
}

I’ve found the above code here.

Two Questions:

  1. why do we need to do setLength()? without which I am getting java.lang.StringIndexOutOfBoundsException: String index out of range: 0

  2. ‘ttr’ and three junk chars are coming when I run this program with parameters – “teeter” and “e”. How to remove the unused whitespaces in the buffer?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T19:26:44+00:00Added an answer on May 22, 2026 at 7:26 pm

    Why not just use replaceAll? java.lang.String.replaceAll

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