Question

   public static void main(String argv[]){
         String a="0700";
         Scanner s = new Scanner(a);
         while(s.hasNextLong()){
              System.out.print(s.nextLong()+",");
         }

Result will be “700,” not the “448”.

Answer 1

By default the scanner assumes that the number is in base 10 and will ignore the leading 0s. You can specify another radix if you want – the code below prints 448:

public static void main(String[] args) {
    String a = "0700";
    Scanner s = new Scanner(a);
    while (s.hasNextLong(8)) { //make sure the number can be parsed as an octal
        System.out.print(s.nextLong(8)); //read as an octal value
    }
}