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Home/ Questions/Q 8132177
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T09:16:58+00:00 2026-06-06T09:16:58+00:00

public void EditAndSave(String fileName) { Bitmap b = new Bitmap(fileName); /** * Edit bitmap

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public void EditAndSave(String fileName) {
    Bitmap b = new Bitmap(fileName);
    /**
    * Edit bitmap b... draw stuff on it...
    **/
    b.Save(fileName); //<---------Error right here
    b.Dispose();
}

My code is similar to the above code. When i try to save the file i just opened, it won’t work. When i try saving it with a different path, it works fine. Could it be that the file is already open in my program so it cannot be written to? I’m very confused.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T09:16:59+00:00Added an answer on June 6, 2026 at 9:16 am

    You are correct in that it is locked by your program and therefore you can’t write to it. It’s explained on the msdn-page for the Bitmap class (http://msdn.microsoft.com/en-us/library/3135s427.aspx).

    One way around this (from the top of my head, might be easier ways though) would be to cache image in a memorystream first and load it from there thus being able to close the file lock.

        static void Main(string[] args)
        {
            MemoryStream ms = new MemoryStream();
            using(FileStream fs = new FileStream(@"I:\tmp.jpg", FileMode.Open))
            {
                byte[] buffer = new byte[fs.Length];
                fs.Read(buffer, 0, buffer.Length);
                ms.Write(buffer, 0, buffer.Length);
            }
    
            Bitmap bitmap = new Bitmap(ms);
    
            // do stuff
    
            bitmap.Save(@"I:\tmp.jpg");
        }
    
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