Question

public void foo(Integer... ids) {
    Integer... fIds = bar(ids);
}

public void bar(Integer... ids) {
// I would like to eliminate few ids and return a subset. How should I declare the return argument 
}

How should I declare the return type for bar?

Answer 1

You can refer to vararg parameters as an array.

public Integer[] bar(Integer... ids) {
..
}

See varargs docs

It is still true that multiple arguments must be passed in an array, but the varargs feature automates and hides the process

To the jvm this is actually an array, and the compiler has hidden the creation of the array.