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Editorial Team
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Asked: 2026-06-01T22:18:05+00:00

public void Foo<T>(Func<T> bar) where T: IMyInterface { Func<IMyInterface> func = bar; } It

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public void Foo<T>(Func<T> bar)
 where T: IMyInterface
{
   Func<IMyInterface> func = bar;
}

It has been a while since I’d understood covariance, but shouldn’t this compile?

Anything bar can return is also an IMyInterface. What seems to be the problem?

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1 Answer

  1. Editorial Team

    Is this a covariance bug in C# 4?

    the correct code is:

    public void Foo<T>(Func<T> bar)
 where T: class, IMyInterface
{
   Func<IMyInterface> func = bar;
}
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