public void wahey(List<Object> list) {}
wahey(new LinkedList<Number>());
The call to the method will not type-check. I can’t even cast the parameter as follows:
wahey((List<Object>) new LinkedList<Number>());
From my research, I have gathered that the reason for not allowing this is type-safety. If we were allowed to do the above, then we could have the following:
List<Double> ld;
wahey(ld);
Inside the method wahey, we could add some Strings to the input list (as the parameter maintains a List<Object> reference). Now, after the method call, ld refers to a list with a type List<Double>, but the actual list contains some String objects!
This seems different to the normal way Java works without generics. For instance:
Object o;
Double d;
String s;
o = s;
d = (Double) o;
What we are doing here is essentially the same thing, except this will pass compile-time checks and only fail at run-time. The version with Lists won’t compile.
This leads me to believe this is purely a design decision with regards to the type restrictions on generics. I was hoping to get some comments on this decision?
What you are doing in the “without generics” example is a cast, which makes it clear that you are doing something type-unsafe. The equivalent with generics would be:
Which behaves the same way (compiles, but fails at runtime). The reason for not allowing the behavior you’re asking about is because it would allow implicit type-unsafe actions, which are much harder to notice in code. For example:
This looks perfectly fine and type-safe until you call it like this:
Which also looks type-safe, because you as the caller don’t necessarily know what Foo is going to do with its parameters.
So in that case you have two seemingly type-safe bits of code, which together end up being type-unsafe. That’s bad, because it’s hidden and therefore hard to avoid and harder to debug.