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Home/ Questions/Q 6531101
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T09:50:13+00:00 2026-05-25T09:50:13+00:00

puts [1,2,3].map do |x| x + 1 end.inspect With ruby 1.9.2 this returns <Enumerator:0x0000010086be50>

  • 0
puts [1,2,3].map do |x| 
  x + 1 
end.inspect

With ruby 1.9.2 this returns

<Enumerator:0x0000010086be50>

ruby 1.8.7:

# 1
# 2
# 3

assigning a variable…

x = [1,2,3].map do |x| 
  x + 1 
end.inspect

puts x

[2, 3, 4]

Moustache blocks work as expected:

puts [1,2,3].map { |x| x + 1 }.inspect

[2, 3, 4]

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  1. Editorial Team
    Editorial Team
    2026-05-25T09:50:13+00:00Added an answer on May 25, 2026 at 9:50 am
    puts [1,2,3].map do |x| 
      x + 1 
    end.inspect
    

    Is parsed as:

    puts([1,2,3].map) do |x| 
      x + 1 
    end.inspect
    

    I.e. map is called without a block (which will make it return the unchanged array in 1.8 and an enumerator in 1.9) and the block is passed to puts (which will just ignore it).

    The reason that it works with {} instead of do end is that {} has different precedence so it’s parsed as:

    puts([1,2,3].map { |x| x + 1 }.inspect)
    

    Similarly the version using a variable works because in that case there is simply no ambiguity.

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