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Home/ Questions/Q 9212227
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T01:28:26+00:00 2026-06-18T01:28:26+00:00

Python beginner here. Let’s say that I have something at the end of my

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Python beginner here. Let’s say that I have something at the end of my script that queries info from a system and dumps it into this format:

print my_list_of_food(blah)

and it outputs a list like:

('Apples', 4, 4792320)
('Oranges', 2, 2777088)
('Pickles', 3, 4485120)
('Pumpkins', 1, 5074944)
('more stuff', 4545, 345345)

How do I then sort that output based on the 2nd field so that it would look like this:

('Pumpkins', 1, 5074944)
('Oranges', 2, 2777088)
('Pickles', 3, 4485120)
('Apples', 4, 4792320)

Other than importing a bash command to cut -d "," -f 2 | head 4 I’d rather use python. I know I can use sorted or sort to sort an existing tuple or dictionary but I’m not sure of how to sort the output of a print. I’ve done some research and everything points to implementing sort into my script instead of sorting a print output but who knows, maybe someone has a solution. Thanks.

UPDATE:

Thanks everyone. I’ve tried to make all of the solutions work but I keep getting this error:

File "test.py", line 18, in <lambda>
    print sorted(my_list_of_food(blah), key=lambda x: x[1])
TypeError: 'int' object is unsubscriptable

File "test.py", line 18, in <lambda>
    print(sorted(my_list_of_food(blah), key=lambda k: k[1]))
TypeError: 'int' object is unsubscriptable

I tried to include this at the beginning of the script:

from __future__ import print_function 

but no luck.

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  1. Editorial Team
    Editorial Team
    2026-06-18T01:28:27+00:00Added an answer on June 18, 2026 at 1:28 am

    You can use the key argument to the sort. In your case,

    print(sorted(list_of_food, key=lambda k:k[1]))
    

    will do the trick. The key function should return an integer, usually.

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