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Home/ Questions/Q 174835
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Asked: May 11, 20262026-05-11T13:35:36+00:00 2026-05-11T13:35:36+00:00

Question: How to display the value of a C++ iterator using WinDbg, illustrated below:

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Question:

How to display the value of a C++ iterator using WinDbg, illustrated below:

for (vector<string>::iterator i = args.begin(); i != args.end(); i++) //omitted //for instance: } else if (*i == '-i') {//attempting to display the value of *i         ++i;         if (!::PathFileExistsA(i->c_str()))         { 

Note:

Using ?? evaluate C++ expression command, which displays the following:

0:000> ?? i  class std::_Vector_iterator<std::basic_string<char, std::char_traits<char>, std::allocator<char> >, std::allocator<std::basic_string<char, std::char_traits<char>, std::allocator<char> > > >     +0x000 _Mycont          : 0x0012ff40 std::_Container_base_secure    +0x004 _Mynextiter      : (null)     +0x008 _Myptr           : 0x009c6198   std::basic_string<char,std::char_traits<char>,std::allocator<char> > 
  • Can another command display/print the value of *i – please correct me if I’m wrong
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1 Answer

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  1. 2026-05-11T13:35:37+00:00Added an answer on May 11, 2026 at 1:35 pm

    Try:

    dt -r i 

    Which will recursively dump the iterator. One of the members should be the info you seek. Verbose, but effective.

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