Question

Question:

I need to get the DATE ONLY (= date WITHOUT time) with an ODBC escape sequence.

However

SELECT 
     {fn CONVERT(SomeTable.Col_With_DateTime_Value, SQL_DATE)}
FROM SomeTable

does return the column as datetime value (date WITH time).

Is there any ODBC function I can use to get the date value only ?

Note:
This is not a duplicate question.
I know one can use the non-ODBC convert function, like

CONVERT(char(8),  getdate(), 112) AS v112_ISO  
CONVERT(char(10), getdate(), 104) AS v104_XML  

but I really need an ODBC function for compatibility reasons.

Answer 1

You could use this:

select {fn convert({fn timestampdiff(SQL_TSI_DAY, 0, DatetimeCol)}, SQL_DATE)}
from SomeTable

Works in the environments I have available to test on (SQL Server 2000-2012).

Update:

Here is another way that I believe could be faster than using convert.

select {fn timestampadd(SQL_TSI_DAY, {fn timestampdiff(SQL_TSI_DAY, 0, DatetimeCol)}, 0)} 
from SomeTable