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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T19:56:48+00:00 2026-05-26T19:56:48+00:00

Question says it all. If I have this for a 96-bit field: uint32_t flags[3];

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Question says it all.

If I have this for a 96-bit field:

uint32_t flags[3]; //(thanks @jalf!)

How do I best go about accessing this, given that my subfields therein may lie over the 32-bit boundaries (eg. a field that runs from bit 29 to 35)?

I need my accesses to be as fast as possible, so I’d rather not iterate over them as 32-bit elements of an array.

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  1. Editorial Team
    Editorial Team
    2026-05-26T19:56:48+00:00Added an answer on May 26, 2026 at 7:56 pm

    [This answer is valid for C (and by extension, for C++ as well).]

    The platform-independent way is to apply bit-masks and bit-shifts as appropriate.

    So to get your field from 29 to 35 (inclusive):

      (flags[1] & 0xF)        << 3
    | (flags[0] & 0xE0000000) >> 29  // The bitmask here isn't really needed, but I like symmetry!
    

    Obviously, you could write a class/function/macro to automate this.

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