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Home/ Questions/Q 765813
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T16:56:48+00:00 2026-05-14T16:56:48+00:00

Question What is the (non-trivial) difference between the following two x86 instructions? 39 /r

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Question

What is the (non-trivial) difference between the following two x86 instructions?

39 /r    CMP r/m32,r32   Compare r32 with r/m32
3B /r    CMP r32,r/m32   Compare r/m32 with r32

Background

I’m building a Java assembler, which will be used by my compiler’s intermediate language to produce Windows-32 executables.

Currently I have following code:

final ModelBase mb = new ModelBase(); // create new memory model
mb.addCode(new Compare(Register.ECX, Register.EAX)); // add code
mb.addCode(new Compare(Register.EAX, Register.ECX)); // add code

final FileOutputStream fos = new FileOutputStream(new File("test.exe"));
mb.writeToFile(fos);
fos.close();

To output a valid executable file, which contains two CMP instruction in a TEXT-section. The executable outputted to “text.exe” will do nothing interesting, but that’s not the point. The class Compare is a wrapper around the CMP instruction.

The above code produces (inspecting with OllyDbg):

Address   Hex dump                 Command
0040101F  |.  3BC8                 CMP ECX,EAX
00401021  |.  3BC1                 CMP EAX,ECX

The difference is subtle: if I use the 39 byte-opcode:

Address   Hex dump                 Command
0040101F  |.  39C1                 CMP ECX,EAX
00401021  |.  39C8                 CMP EAX,ECX

Which makes me wonder about their synonymity and why this even exists.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T16:56:48+00:00Added an answer on May 14, 2026 at 4:56 pm

    It doesn’t matter which opcode you use if you compare two registers. The only difference is when comparing a register with a memory operand, as the opcode used determines which will be subtracted from which.

    As for why this exists: The x86 instruction format uses the ModR/M byte to denote either a memory address or a register. Each instruction can only have one ModR/M value, which means it can only access one memory address (not including special instructions like MOVSB). So this means that there can’t be a general cmp r/m32, r/m32 instruction, and we need two different opcodes: cmp r/m32, r32 and cmp r32, r/m32. As a side effect, this creates some redundancy when comparing two registers.

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