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Home/ Questions/Q 8742489
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T11:30:39+00:00 2026-06-13T11:30:39+00:00

Quick one I think. 2d problem in Cocos2d and xcode. I have CGPoint currPoint;

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Quick one I think. 2d problem in Cocos2d and xcode.

I have

CGPoint currPoint;
float lineLength;
float angle;

Now, I need to find the point that is lineLength away from currPoint at angle Degrees.

Tried to search, but the answers i have found aren’t quite what I was looking for. Would appreciate anyone pointing out the (I assume) pretty simple math I have overlooked.

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  1. Editorial Team
    Editorial Team
    2026-06-13T11:30:40+00:00Added an answer on June 13, 2026 at 11:30 am

    From the top of my head:

    CGPoint endPoint;
    endPoint.x = sinf(CC_DEGREES_TO_RADIANS(angle)) * lineLength;
    endPoint.y = cosf(CC_DEGREES_TO_RADIANS(angle)) * lineLength;
    endPoint = ccpAdd(currPoint, endPoint);
    

    Not sure where the vector points to, if it may be rotated by 90, 180 or 270 degrees. If so, just add/subtract that amount from angle.

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