Question

Quick Python question: How do I access data from a nested list like this:

{'album': [u'Rumours'], 'comment': [u'Track 3'], 'artist': [u'Fleetwood Mac'], 'title': [u'Never Going Back Again'], 'date': [u'1977'], 'genre': [u'Rock'], 'tracknumber': [u'03']}

I tried listname[0][0] but it returns the error:
AttributeError: 'int' object has no attribute 'lower'

So how would I go about doing this?

Answer 1

This is not a list. This is a dictionary.

The dictionary is not ordered, and thus it cannot be accessed through a numeric index*.

You must refer to to it like this: listname['album']

The above will return you a list with one element (which happens to be a list): [u'Rumours'], to acces a list, you do as usual.

So altogether:

listname['album'][0] 
# Will output the string inside the list.

Notice that the list could have more elements, so you would refer them like so [0],[1] etc.

Take a look at the docs for more information.

---

*You can do:

d = {2:"a",1:"b"}
print d[1] ### prints string b

What I meant is that you don’t use zero based indexes, you use keys that can be “whatever you want” and this keys refer to values.