Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 9063223
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 16, 20262026-06-16T15:56:20+00:00 2026-06-16T15:56:20+00:00

Rails provides a timestamp like follows: 2012-12-21T01:09:32Z How can I use JavaScript to determine

  • 0

Rails provides a timestamp like follows: 2012-12-21T01:09:32Z

How can I use JavaScript to determine how many days old the timestamp is?

Thanks

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-16T15:56:21+00:00Added an answer on June 16, 2026 at 3:56 pm

    You can use new Date('2012-12-21T01:09:32Z') to turn the string into a Date object. Then use simple arithmetic:

    var dateStr = '2012-12-21T01:09:32Z',
    daysAgo = (new Date() - new Date(dateStr)) / 86400 / 1000;
    
    if (daysAgo > 7) {
        // more than 7 days ago
    }
    

    You may want to use Math.floor(daysAgo) or Math.ceil(daysAgo) to round the results down or up, depending on your situation.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Our app provides an API that people can use to submit URLs like this:
Many Rails helpers use an idiomatic options hash as their last argument; Ruby automatically
using rails with Paperclip, I can use the following to get the filename during
Rails provides label references for associations in fixtures like this: ### in pirates.yml reginald:
Rails provides named routes . Routes helper can be called using path or url
How can I temporarily disable the asset pipeline functionality that Rails 3.1 provides? (I
Maybe I'm stupid but Rails provides this nifty syntax for generating URL's like so:
I'm working on a Rails-based web service that provides data about various sports team
How would I create the following scenario that rails can provide for carrierwave, using
I am working on a Rails application that has user authentication which provides an

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.