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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T12:55:18+00:00 2026-05-15T12:55:18+00:00

Reading from a pipe: unsigned int sample_in = 0; //4 bytes – 32bits, right?

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Reading from a pipe:

    unsigned int sample_in = 0; //4 bytes - 32bits, right?


      unsigned int len = sizeof(sample_in); // = 4 in debugger
      while (len > 0)
   {
    if (0 == ReadFile(hRead,
                          &sample_in,
                          sizeof(sample_in),
                          &bytesRead,
                          0))
    {
                    printf("ReadFile failed\n");

    }

    len-= bytesRead; //bytesRead always = 4, so far

   }

In the debugger, first iteration through:

sample_in = 536739282 //36 bits?  

How is this possible if sample in is an unsigned int? I think I’m missing something very basic, go easy on me!

Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-15T12:55:19+00:00Added an answer on May 15, 2026 at 12:55 pm

    Judging from your comment that says //36 bits? I suspect that you’re expecting the data to be sent in a BCD-style format: In other words, where each digit is a number that takes up four bits, or two digits per byte. This way would result in wasted space however, you would use four bits, but values “10” to “15” aren’t used.

    In fact integers are represented in binary internally, thus allowing a 32-bit number to represent up to 2^32 different values. This comes out to 4,294,967,295 (unsigned) which happens to be rather larger than the number you saw in sample_in.

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