Question

Reading “PHP & jQuery Cookbook” right now and it gives this example for using json_decode()

<?php
$json = <<<JSON
{
  "origin":"Delhi",
  "destination":"London",
  "passengers":
  [
    {
      "name":"Mr. Perry Mason",
      "type":"Adult",
      "age":28
    }
    {
      "name":"Miss Irene Adler",
      "type":"Adult",
      "age":25
    }
  ],
  "travelDate":"17-Dec-2010"
}
JSON;

$objJson = json_decode($json);
echo ($objJson);

?>

The code just gives me a blank page when I run it. Is there something invalid about that JSON? Because json_decode() doesnt even seem to see it.

Answer 1

rather use print_r() than using echo to see if it prints

but a comma is missing from your JSON input

it should be like this

 {
  "name":"Mr. Perry Mason",
  "type":"Adult",
  "age":28
},
{
  "name":"Miss Irene Adler",
  "type":"Adult",
  "age":25
}