Real Dumb question. I figured I would have gotten this straight by now, but I am obviously missing something. I want my function to fire as soon as the page loads to check the value of a variable and make a button appear or dissapear based on that value. But the function I wrote never gets called. I place the function inside a $.Load() and $(document).ready jquery call. How can I get this function to fire?
$(document).ready(function () {
debugger;
(function () {
debugger;
var $b = '<%=toggle %>';
var buttonTog = $("#test1");
var buttonTog1 = $("#Submit1");
if($b=="1")
{
debugger;
buttonTog1.css({
display: 'block'
})
buttonTog.css({
display: 'none'
});
}
else if($b=="0")
{
debugger;
buttonTog1.css({
display: 'none'
})
buttonTog.css({
display: 'block'
});
}
});
...
});
As you can see, I have multiple debugger statements in there that just don’t get hit… When I hit $(document).ready and I get into the first debugger statement, It simply doesn’t touch the next function? I don’t get it? It goes right over it? Can you not call a function inside the .ready(function())? Definitly need to get some research done.
You define an anonymous function but you never call it. Here’s how to auto-invoke the anonymous function:
This being said, I can hardly see the usefulness of using this anonymous auto-invoking function inside the
document.readycallback which itself is an anonymous function. Things start to get really private here 🙂You could simply write the code inside it:
I suspect that you might be missing some important concepts about the
$(document).readyfunction and its syntax. I would recommend you checking the documentation for more examples.