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Home/ Questions/Q 6072697
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T10:11:19+00:00 2026-05-23T10:11:19+00:00

real_order = [ ‘1’, ‘2’, ‘3’, ‘4’]; friends = [ { name: ‘jess’, id:

  • 0
real_order = [ '1', '2', '3', '4'];

friends = [ { name: 'jess', id: '4'},
            { name: 'alex', id: '1'},
            { name: 'kat', id: '3' },
            { name: 'bob', id: '2' }
          ] 

How do I make “friends” array “match” the elements in real_order?
The result should be:

[ 
            { name: 'alex', id: '1'},
            { name: 'bob', id: '2' },
            { name: 'kat', id: '3' },
            { name: 'jess', id: '4'},
          ] 

What is the most efficient solution?

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  1. Editorial Team
    Editorial Team
    2026-05-23T10:11:20+00:00Added an answer on May 23, 2026 at 10:11 am

    Here is some code that would do it:

    var i, d = {}, result = [];
    for(i=0; i<friends.length; ++i)
    {
        d[friends[i].id] = friends[i];
    }
    
    for(i=0; i<real_order.length; ++i)
    {
        result.push(d[real_order[i]]);
    }
    

    What this does is it creates a dictionary keyed on each of the friends’ id, then uses the second array to do a look up and construct the new array. The resulting reordered array is stored in result.

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