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Home/ Questions/Q 3426574
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T06:43:56+00:00 2026-05-18T06:43:56+00:00

Recently I came across a problem that asks to find out the non-unique characters

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Recently I came across a problem that asks to find out the non-unique characters in a string without any additional buffer. I interpreted this problem to be an in-place sort of the characters in the string and then iterating through it in order to track down the non-unique characters.

Another solution that can have O(1) space and O(n^2) run-time is having two ‘for’ loops going over the string to track down any pairs of characters that are common.

What I need is to sort the string in atleast O(nlogn) time with O(1) space.

Is there a simple/elegant way to do an in-place sort of characters in O(nlgn) with O(1) space?

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  1. Editorial Team
    Editorial Team
    2026-05-18T06:43:57+00:00Added an answer on May 18, 2026 at 6:43 am

    There is a really nice comparison grid of sorting algorithms on wikipedia.

    http://en.wikipedia.org/wiki/Sorting_algorithm#Comparison_of_algorithms

    Heapsort and Smoothsort seem to be your obvious winners. Depending on your language you may or may not already have these, though I’m sure in most cases they’re probably a library away.

    There’s a Java impl that at a glance claims to heapsort a set of anything Comparable.
    http://www.java-tips.org/java-se-tips/java.lang/heap-sort-implementation-in-java.html

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