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Home/ Questions/Q 7082969
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T07:07:14+00:00 2026-05-28T07:07:14+00:00

Recently, I find myself writing code like this: for name in dir( object ):

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Recently, I find myself writing code like this:

for name in dir( object ):
    if name.startswith( '__' ) : continue
    ...

Is there a more pythonic way to access the object’s “public” namespace?

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  1. Editorial Team
    Editorial Team
    2026-05-28T07:07:15+00:00Added an answer on May 28, 2026 at 7:07 am

    You can prepare list of “public” attributes (as list or as generator) before:

    >>> public_props = (name for name in dir(object) if not name.startswith('_'))
    >>> for name in public_props:
        print name
    

    But please read a note about dir() function in the documentation:

    Note Because dir() is supplied primarily as a convenience for use at an interactive prompt, it tries to supply an interesting set of names more than it tries to supply a rigorously or consistently defined set of names, and its detailed behavior may change across releases. For example, metaclass attributes are not in the result list when the argument is a class.

    You should also be aware, that any class can implement __dir__() method that may return a list of names that do not necessarily correspond to the names of the attributes. In other words, dir(something) does not guarantee that the result will return attributes of something.

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