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Home/ Questions/Q 8628513
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T08:33:50+00:00 2026-06-12T08:33:50+00:00

Recently I read a piece of code like this: template <unsigned long size> class

  • 0

Recently I read a piece of code like this:

template <unsigned long size>
class FooBase
{
  bool m_bValid;
  char m_data[size];
};

template <class T>
class Foo : public FooBase<sizeof(T)>
{
  // it's constructor
  Foo(){};
  Foo(T const & t) {construct(t); m_bValid = (true);}

  T const * const GetT() const { return reinterpret_cast<T const * const>(m_data); }
  T * const GetT() { return reinterpret_cast<T * const>(m_data);}

  // could anyone help me understand this line??
  void construct(T const & t) {new (GetT()) T(t);}
};

I have sliced the code to make sure it’s not that complicated, the main question is about the construct(T const & t) function.

What does new (GetT()) T(t); exactly means?

btw, which version of GetT() is called?

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  1. Editorial Team
    Editorial Team
    2026-06-12T08:33:51+00:00Added an answer on June 12, 2026 at 8:33 am

    What does new (GetT()) T(t); exactly means?

    It is Placement new, it allows you to place an object at a particular location in memory, which is returned by Get().

    which version of GetT() is called?

    The Second one.
    Whenever the compiler has option of choosing between a const and a non-const function, it chooses the non-const version.
    Specifically, in this case as @James points out in comments:
    Non-const version is given preference because the member function which calls it is non-const.

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