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Home/ Questions/Q 6803949
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T19:24:24+00:00 2026-05-26T19:24:24+00:00

Recently, in the gcc-trunk sources was implemented the user defined literals. Tell me please,

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Recently, in the gcc-trunk sources was implemented the “user defined literals”.
Tell me please, do I understand correctly that I can`t define a “user defined literals” for variadic char template?

template<char... chars>
int operator"" _call() { return sizeof...(chars); }
...
std::cout << "method"_call;

Up.

I don`t understand why this expression is allowed:

template<char... chars>
int operator"" _call() { return sizeof...(chars); }
...
std::cout << 12345566_call;

and this one is disallowed:

template<char... chars>
int operator"" _call() { return sizeof...(chars); }
...
std::cout << method_call;

?

What’s the point?

Up.
this is because of the ambiguity?

Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T19:24:25+00:00Added an answer on May 26, 2026 at 7:24 pm

    method_call is a valid identifier As is for example some_call or my_call. Now imagine how much code would be broken if such identifiers were allowed to be redefined by operator"".

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