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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T09:18:31+00:00 2026-05-26T09:18:31+00:00

Referring to this construct, posting a full example would be a little too big:

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Referring to this construct, posting a full example would be a little too big:

__thread char* buf;
buf = malloc(1000);

Valgrind says the bytes are “definitely” lost. Shouldn’t they just be “still reachable”?

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  1. Editorial Team
    Editorial Team
    2026-05-26T09:18:32+00:00Added an answer on May 26, 2026 at 9:18 am

    Because the allocated memory is not thread-local. It’s shared by all of the threads.

    The variable is, on the other hand, thread local so once it’s out of scope that allocated memory will be definitely lost (if there are no copies of that pointer elsewhere.. and obviously there aren’t because valgrind reports definitely lost)

    You have to free it.

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