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Home/ Questions/Q 6545207
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T11:33:28+00:00 2026-05-25T11:33:28+00:00

Regarding the code below, how does the interpreter know that event has attribute .keyCode.

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Regarding the code below, how does the interpreter know that event has attribute .keyCode. This code works, I just don’t understand completely why, and more so were is this documented. How does it know what type of object event is. What if I would have called it ‘e’ or ‘e1’. Where is the method prototype f1(Event) documented?

function b0(event) 
  {if (event.keyCode==13) 
    {i4(); 
    return false;}} 


function o5('f4b_',b0); 

o5(a,b){document.getElementById(a).onkeypress=b;}

where the element id a is an input text box.

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  1. Editorial Team
    Editorial Team
    2026-05-25T11:33:29+00:00Added an answer on May 25, 2026 at 11:33 am

    The name of event is irrelevant, inside the function it’s just another variable. You can rename it to JellyMan, and if you rename if (event.keyCode==13) to if (JellyMan.keyCode==13) it will work fine.

    The type of event is determined by the script at run-time. The interpreter does not know that event has an attribute of .keyCode – if you tried to call it, and passed in a parameter that isn’t the correct type: b0('wheee, break it'); then it will fail.

    When the author wrote the script, he decided that function b0 would take one parameter (he called it event) and it would be a eventHandler – this doesn’t get specified anywhere, it’s just assumed that nobody’s going to call it with something else. All eventHandlers have a .keyCode attribute, so it’s therefore assumed that the object being passed in has one.

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