Regarding Umbraco XSLT version 1.
I have aprox. 150 news items in XML. Lets say like this (all is pseudocode until I get more familiar with this xml/xslt):
<news>
<data alias=date>2008-10-20</data>
</news>
<news>
<data alias=date>2009-11-25</data>
</news><news>
<data alias=date>2009-11-20</data>
</news> etc. etc....
I would like to run through the XML and create html-output as a news archive. Something like (tags not important):
2008
Jan
Feb
...
2009
Jan
Feb
Mar
etc. etc.
I can only come up with a nested for-each (pseudocode):
var year_counter = 2002
var month_counter = 1
<xsl:for-each select="./data [@alias = 'date']=year_counter">
<xsl:for-each select="./data [@alias = 'date']=month_counter">
<xsl:value-of select="data [@alias = 'date']>
"...if month_counter==12 end, else month_counter++ ..."
</xsl:for-each>
"... year_counter ++ ..."
</xsl:for-each>
But a programmer pointet out that looping through 10 years will give 120 loops and that is bad coding. Since I think Umbraco caches the result I am not so concerned, plus in this case there will be a max. of 150 records.
Any clues on how to sort and output many news items and group them in year and group each year in months?
Br. Anders
For the following solution I used this XML file:
and this XSLT 1.0 transformation:
When the transformation is applied, the following output is produced:
It has the right structure already, you can adapt actual appearance to your own needs.
The solution is a two-phase Muenchian grouping approach. In the first phase, news items are grouped by year, in the second phase by year-month.
Please refer to my explanation of
<xsl:key>andkey()over here. You don’t need to read the other question, though it is a similar problem. Just read the lower part of my answer.