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Home/ Questions/Q 7940911
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T23:30:32+00:00 2026-06-03T23:30:32+00:00

RegEx = new RegExp(sourcevalue, gi); temp[i] = Selectors[i].cssText.replace(RegEx, targetvalue); where sourcevalue = rgb(255,0,0) and

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RegEx = new RegExp(sourcevalue, "gi");

temp[i] = Selectors[i].cssText.replace(RegEx, targetvalue);

where sourcevalue = rgb(255,0,0) and targetvalue = #FFFFFF, but sourcevalue is not replaced by targetvalue, why?

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  1. Editorial Team
    Editorial Team
    2026-06-03T23:30:34+00:00Added an answer on June 3, 2026 at 11:30 pm

    Because sourcevalue is a correct Javascript regular expression but it’s not working the way you expected. There are special characters in regular expression like the () parentheses. They are used to group parts of regular expressions. To use them with their “literal” meaing you’ll have to escape them using backslashes

    var RegEx = /rgb\(255,0,0\)/gi;
    
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