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Home/ Questions/Q 319649
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T08:40:51+00:00 2026-05-12T08:40:51+00:00

Related to this question Given this function: public static <S extends CharSequence> S foo(S

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Related to this question

Given this function:

public static <S extends CharSequence> S foo(S s) {
  return (S) new StringBuilder(s);
}

Why does this invocation execute without exception:

foo("hello");

But this one throws ClassCastException?

System.out.println(foo("hello"));
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  1. Editorial Team
    Editorial Team
    2026-05-12T08:40:51+00:00Added an answer on May 12, 2026 at 8:40 am

    Generics in Java 5/6 are type-erased, which means that any generic type is fundamentally just an Object type (or whatever the least common denominator type is, which is in this case CharSequence) at runtime. The appropriate casts are inserted wherever needed. So your method gets type-erased to something that looks like this:

    public static CharSequence foo(CharSequence s) {
      return (CharSequence) new StringBuilder(s);
    }
    

    And your call gets type-erased to this:

    System.out.println((String)foo("hello"));
    

    Apparently Java won’t bother inserting the (String) cast if the return value is never used—why bother?

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