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Home/ Questions/Q 995313
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T06:42:14+00:00 2026-05-16T06:42:14+00:00

$result = $conn->query(SELECT * FROM temp_users WHERE reg_code =’$passkey’); This works: if($result->num_rows == 1){

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$result = $conn->query(“SELECT * FROM temp_users WHERE reg_code =’$passkey'”);

This works:

if($result->num_rows == 1){

values from print_r($result);

mysqli_result Object ( [current_field] => 0 [field_count] => 11 [lengths] => [num_rows] => 1 [type] => 0 )

but $result->username where username is a field in the db shows up blank?

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  1. Editorial Team
    Editorial Team
    2026-05-16T06:42:14+00:00Added an answer on May 16, 2026 at 6:42 am

    Yes, because you need to fetch a row from the $result. It can be done via function: http://www.php.net/manual/en/mysqli-result.fetch-array.php and a few more – check PHP manual.

    From manual:

    /* associative array */
    $row = $result->fetch_array(MYSQLI_ASSOC);
    echo $row["username"];
    
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