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Home/ Questions/Q 620591
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T18:46:50+00:00 2026-05-13T18:46:50+00:00

$result = mysql_query(SELECT blog_title,body FROM blog WHERE post_id=’$id’ LIMIT 1) or die (mysql_error()); while

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$result = mysql_query("SELECT blog_title,body FROM blog WHERE post_id='$id' LIMIT 1") or die (mysql_error());

while ($line = mysql_fetch_assoc($result)){
 $tasks[] = $line;
 $group = $tasks['blog_title'];
 $smarty->assign('view', $tasks);
 $smarty->assign('group', $group);
//here the error.i want to assign blog_title to title
 $smarty->assign('title', "Blog - $group");

newbie,need help.i want to assign blog_title to title
any idea?

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  1. Editorial Team
    Editorial Team
    2026-05-13T18:46:50+00:00Added an answer on May 13, 2026 at 6:46 pm

    You don’t need $tasks. This variable messes your script up due to the [] you’re using.
    [] = works just like creating an array using array and applying array_push to it.

    Here’s what you want to achieve:

    $result = mysql_query("SELECT blog_title,body FROM blog WHERE post_id='$id' LIMIT 1") or die (mysql_error());
    
    while ($line = mysql_fetch_assoc($result)){
      $group = $line['blog_title'];
      $smarty->assign('view', $line);
      $smarty->assign('group', $group);
      $smarty->assign('title', "Blog - $group");
    }
    

    By the way: in the first line ($result =... ), ensure that $id is properly escaped (see mysql_real_escape).

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