Question

$result2 = mysql_query($query, $con);
            while($data2 = mysql_fetch_assoc($result2))
            {
                $x = $data2["x"];
                $y = $data2["y"];
                echo "$x";
                echo "$y";
                if($x<0 && $y<0)
                {
                    echo "village: $data[village]  ";
                    echo "player: $data[player]  ";
                    echo "position: ($data[x]|$data[y])<br>";
                }
                else if($x>0 && $y>0)
                {
                    echo "village: $data[village]  ";
                    echo "player: $data[player]  ";
                    echo "position: ($data[x]|$data[y])<br>";
                }
                else if($x>0 && $y<0)
                {
                    echo "village: $data[village]  ";
                    echo "player: $data[player]  ";
                    echo "position: ($data[x]|$data[y])<br>";
                }
            }

I am getting the error

Notice: Undefined index: y in C:\xampp\htdocs\debal\nw_check_exec.php on line 48

Notice: Undefined index: x in C:\xampp\htdocs\debal\nw_check_exec.php on line 47

line 47 and line 48 are:-

$x = $data2["x"];
$y = $data2["y"];

I think i have done all things properly, and i am unable to figure out the cause of the error.

Answer 1

Properbly the $data2 has really no index x so you need to check that and use instat a default value.

You can use for that a small inline if statment:

$x = isset($data2["x"]) ? $data2["x"] : 0;
$y = isset($data2["y"]) ? $data2["y"] : 0;

By the way do you have really defined so much constants? E.g. here:

$data[village]

This means that there must be a constant village maybe with some value “village”?

Maybe you should exchange that with a:

$data["village"]